CF1141F Please, another Queries on Array?

发表于 | 阅读数

没啥好说

考虑质数60个，用二进制保存状态即可。

代码 
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#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define pii pair<ll, ll>
#define mk make_pair
const ll N = 4e5 + 10;
const ll mod = 1e9 + 7;
ll read()
{
    ll x = 0, f = 1;
    char c = getchar();
    while (c < '0' || c > '9')
    {
        if (c == '-')
            f = -1;
        c = getchar();
    }
    while (c >= '0' && c <= '9')
        x = (x << 1) + (x << 3) + c - '0', c = getchar();
    return x * f;
}
ll qpow(ll a, ll x, ll mo)
{
    ll res = 1;
    while (x)
    {
        if (x & 1)
            res = 1ll * res * a % mo;
        a = 1ll * a * a % mo;
        x >>= 1;
    }
    return res;
}
const ll SEN = 4e5 + 10;
struct segmentTree
{
    ll sum[SEN << 2], lazy[SEN << 2];
    void addtag(ll pos, ll l, ll r, ll w)
    {
        lazy[pos] |= w;
        sum[pos] |= w;
    }
    void pushdown(ll pos, ll l, ll r)
    {
        if (lazy[pos])
        {
            ll w = lazy[pos];
            ll mid = (l + r) >> 1;
            addtag(pos << 1, l, mid, w);
            addtag(pos << 1 | 1, mid + 1, r, w);
            lazy[pos] = 0;
        }
    }
    void pushup(ll pos)
    {
        sum[pos] = sum[pos << 1 | 1] | sum[pos << 1];
    }
    ll query(ll ql, ll qr, ll pos, ll l, ll r)
    {
        if (ql <= l && r <= qr)
        {
            return sum[pos];
        }
        pushdown(pos, l, r);
        ll mid = (l + r) >> 1;
        ll ans = 0;
        if (ql <= mid)
            ans |= query(ql, qr, pos << 1, l, mid);
        if (qr > mid)
            ans |= query(ql, qr, pos << 1 | 1, mid + 1, r);
        return ans;
    }
    void update(ll ql, ll qr, ll w, ll pos, ll l, ll r)
    {
        if (ql <= l && r <= qr)
        {
            addtag(pos, l, r, w);
            return;
        }
        pushdown(pos, l, r);
        ll mid = (l + r) >> 1;

        if (ql <= mid)
            update(ql, qr, w, pos << 1, l, mid);
        if (qr > mid)
            update(ql, qr, w, pos << 1 | 1, mid + 1, r);
        pushup(pos);
    }
} T1;
struct segmentTree2
{
    ll sum[SEN << 2], lazy[SEN << 2];
    void addtag(ll pos, ll l, ll r, ll w)
    {
        lazy[pos] = 1ll * lazy[pos] * w % mod;
        sum[pos] = 1ll * sum[pos] * qpow(w, r - l + 1, mod) % mod;
    }
    void pushdown(ll pos, ll l, ll r)
    {
        if (lazy[pos] > 1)
        {
            ll w = lazy[pos];
            ll mid = (l + r) >> 1;
            addtag(pos << 1, l, mid, w);
            addtag(pos << 1 | 1, mid + 1, r, w);
            lazy[pos] = 1;
        }
    }
    void pushup(ll pos)
    {
        sum[pos] = 1ll * sum[pos << 1 | 1] * sum[pos << 1] % mod;
    }
    ll query(ll ql, ll qr, ll pos, ll l, ll r)
    {
        if (ql <= l && r <= qr)
        {
            return sum[pos];
        }
        pushdown(pos, l, r);
        ll mid = (l + r) >> 1;
        ll ans = 1;
        if (ql <= mid)
            ans = 1ll * ans * query(ql, qr, pos << 1, l, mid) % mod;
        if (qr > mid)
            ans = 1ll * ans * query(ql, qr, pos << 1 | 1, mid + 1, r) % mod;
        return ans;
    }
    void update(ll ql, ll qr, ll w, ll pos, ll l, ll r)
    {
        if (ql <= l && r <= qr)
        {
            addtag(pos, l, r, w);
            return;
        }
        pushdown(pos, l, r);
        ll mid = (l + r) >> 1;

        if (ql <= mid)
            update(ql, qr, w, pos << 1, l, mid);
        if (qr > mid)
            update(ql, qr, w, pos << 1 | 1, mid + 1, r);
        pushup(pos);
    }
} T2;
ll p[N], cnt = -1;
ll vis[N];
int main()
{
    for (ll i = 2; i <= 300; i++)
    {
        bool flag = 1;
        for (ll j = 2; j < i; j++)
            if (i % j == 0)
                flag = 0;

        if (flag)
            p[++cnt] = i, vis[cnt] = (1 - qpow(i, mod - 2, mod) + mod) % mod;
    }

    ll n = read(), m = read();
    for (ll i = 1; i <= 4 * n; i++)
        T2.sum[i] = T2.lazy[i] = 1;
    for (ll i = 1; i <= n; i++)
    {
        ll x = read();
        ll st = 0;
        for (ll j = 0; j <= cnt; j++)
            if (x % p[j] == 0)
                st |= (1ll << j);
        //cout << x << " " << st << endl;
        T1.update(i, i, st, 1, 1, n);
        T2.update(i, i, x, 1, 1, n);
    }

    for (ll t = 1; t <= m; t++)
    {
        char s[10];
        scanf("%s", s);
        //cout << "---" << endl;
        if (s[0] == 'T')
        {
            ll l = read(), r = read();
            ll ans = 1;
            //cout << l << " " << r << endl;
            ll st = T1.query(l, r, 1, 1, n);

            for (ll i = 0; i <= cnt; i++)
                if ((st & (1ll << i)))
                    ans = 1ll * ans * vis[i] % mod;

            ans = 1ll * ans * T2.query(l, r, 1, 1, n) % mod;
            printf("%d\n", ans);
        }
        else
        {
            ll l = read(), r = read(), x = read();
            ll st = 0;
            for (ll j = 0; j <= cnt; j++)
                if (x % p[j] == 0)
                    st |= 1ll << j;
            T1.update(l, r, st, 1, 1, n);
            T2.update(l, r, x, 1, 1, n);
        }
    }
}